Question:

A person is standing on a weighing-scale and observes that the reading is $60\,kg$ . He then suddenly jumps up and observes that reading goes to $70\,kg$ . Then his maximum upward acceleration is

Updated On: Sep 19, 2024
  • $0$
  • $ 1.4\,m/s^{2}$
  • $ 1.63\,m/s^{2}$
  • $ 9.8\,m/s^{2}$
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The Correct Option is C

Solution and Explanation

Initial reading of the machine is $60\, kg$.
Therefore, mass of the person, $m=60\, kg$ Final reading is $70\, kg$.
Thus, extra force applied on the person is
$\Delta F=(70-60) \times 98=98\, N$
Hence upward acceleration of the person is
$a=\frac{\Delta F}{m}=\frac{98}{60}=1.63\, m / s ^{2}$
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