Question

A person consumes 2.5 liters of water per day. The water quality test indicated that the supplied water has a Pb concentration of 0.6 mg/L. If the weight of the person is 75 kg, the exposure level for Pb for this person from this drinking water source is _________mg/kg/day (rounded off to 2 decimal places).

Answer 1

Correct Answer: 0.02

Step 1: Calculate the daily intake of Pb. \[ \text{Daily Intake of Pb (mg/day)} = \text{Water Consumption (L/day)} \times \text{Pb Concentration (mg/L)} = 2.5 \, \text{L/day} \times 0.6 \, \text{mg/L} = 1.5 \, \text{mg/day} \] Step 2: Calculate the exposure level per kg body weight. \[ \text{Exposure Level (mg/kg/day)} = \frac{\text{Daily Intake of Pb (mg/day)}}{\text{Body Weight (kg)}} = \frac{1.5 \, \text{mg/day}}{75 \, \text{kg}} = 0.02 \, \text{mg/kg/day} \]