Question

A particle starts from rest and accelerates uniformly at 4 m/s\(^2\). What is the distance covered in the 5th second?

• A. 36 m
• B. 18 m
• C. 44 m
• D. 20 m

Hint:

Formula: For uniformly accelerated motion, use \( s_n = u + \frac{a}{2}(2n - 1) \) to find distance in the \(n^{\text{th}}\) second.

Answer 1

The Correct Option is B

• Step 1: Use the formula for distance in the \(n^{\text{th}}\) second:
  \[ s_n = u + \frac{a}{2}(2n - 1) \] where \( u = 0 \), \( a = 4 \, \text{m/s}^2 \), \( n = 5 \)
• Step 2: Substitute values.
  \[ s_5 = 0 + \frac{4}{2}(2 \cdot 5 - 1) = 2 \cdot 9 = \boxed{18 \text{ m}} \] Correct Answer: (A) 18 m