Question:

A particle starting from rest moves upto $20\, s$ with constant acceleration. If $S _1$ is the distance covered in first $10\, s$ and $S_2$ is the distance covered in last $10$ second, then

Updated On: Jul 5, 2022
  • $S_2=S_1$
  • $S_2=2S_1$
  • $S_2=3S_1$
  • $S_2=4S_1$
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The Correct Option is C

Solution and Explanation

$S_1 =\frac{1}{2} at^2 = \frac{1}{2} \times a \times 10^32 = 50a$ $S_1 + S_2 = \frac{1}{2} \times a \times 20^2 = 200 a$ Then $S_2 = 20 \, a - S_1 = 200 \, a - 50 \, a = 150 \, a = 3 \times 50 \, a = 3S_1$
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Concepts Used:

Motion in a straight line

The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion. 

Types of Linear Motion:

Linear motion is also known as the Rectilinear Motion which are of two types:

  1. Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
  2. Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.