Question:

A particle performing uniform circular motion has angular momentum $L$. If its angular frequency is doubled and its kinetic energy halved, then the new angular momentum is

Updated On: Jul 5, 2022
  • $L/4$
  • $4L$
  • $2L$
  • $L/2$
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The Correct Option is A

Solution and Explanation

Angular momentum of a particle performing uniform circular motion $L = I?$ Kinetic energy, $K=\frac{1}{2}\omega^{2}$ Therefore, $L=\frac{2K}{\omega^{2}}\omega=\frac{2K}{\omega}$ $\frac{L_{1}}{L_{2}}=\frac{K_{1}\omega_{2}}{K_{2}\omega_{1}}$ $\frac{L_{1}}{L_{2}}=2\times2=4 L_{1}=\frac{L}{4}$
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Concepts Used:

System of Particles and Rotational Motion

  1. The system of particles refers to the extended body which is considered a rigid body most of the time for simple or easy understanding. A rigid body is a body with a perfectly definite and unchangeable shape.
  2. The distance between the pair of particles in such a body does not replace or alter. Rotational motion can be described as the motion of a rigid body originates in such a manner that all of its particles move in a circle about an axis with a common angular velocity.
  3. The few common examples of rotational motion are the motion of the blade of a windmill and periodic motion.