Question:

A particle of mass m and angular momentum L moves in space where its potential energy is U(r) = kr2 (k > 0) and r is the radial coordinate.
If the particle moves in a circular orbit, then the radius of the orbit is

Updated On: Oct 1, 2024
  • \((\frac{L^2}{mk})^{\frac{1}{4}}\)
  • \((\frac{L^2}{2mk})^{\frac{1}{4}}\)
  • \((\frac{2L^2}{mk})^{\frac{1}{4}}\)
  • \((\frac{4L^2}{mk})^{\frac{1}{4}}\)
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The Correct Option is B

Solution and Explanation

The correct answer is (B) : \((\frac{L^2}{2mk})^{\frac{1}{4}}\)
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