Question

A particle of charge ‘q’, mass ‘m’ and velocity ‘v’, enters perpendicular to a magnetic field ‘B’, force on particle will be

• A. \(qvB\)
• B. \(\frac{q^2vB}{m}\)
• C. \(qvB\)
• D. \(qvB\)

Hint:

The formula for the force on a charged particle moving in a magnetic field is \(F = qvB\), where the direction is perpendicular to both velocity and magnetic field.

Answer 1

The Correct Option is A

The magnetic force on a moving charge is given by: \[ F = qvB \] where \(q\) is the charge, \(v\) is the velocity, and \(B\) is the magnetic field strength.