Question:

A particle moves with constant acceleration of 2 m/s\(^2\) starting from rest. Its velocity after 3 seconds is

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Constant Acceleration Kinematics. Key equations: \(v = u + at\), \(s = ut + \frac{1{2at^2\), \(v^2 = u^2 + 2as\). Use the equation that relates the known and unknown quantities.
Updated On: May 7, 2025
  • 5 m/s
  • 6 m/s
  • 9 m/s
  • 12 m/s
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The Correct Option is B

Solution and Explanation

We use the kinematic equation for velocity under constant acceleration: $$ v = u + at $$ where \(v\) is final velocity, \(u\) is initial velocity, \(a\) is acceleration, and \(t\) is time.
Given: Initial velocity \(u = 0\) m/s (starts from rest).
Acceleration \(a = 2\) m/s\(^2\).
Time \(t = 3\) s.
Substitute the values: $$ v = 0 + (2 \, \text{m/s}^2)(3 \, \text{s}) $$ $$ v = 6 \, \text{m/s} $$ The velocity after 3 seconds is 6 m/s.

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