Question:

A particle moves along Y-axis in such a way that its $ y- $ coordinate varies with time $ t $ according to the relation $ y=3+5t+7{{t}^{2}}. $ The initial velocity and acceleration of the particle are respectively:

Updated On: Jul 19, 2024
  • $ 14m{{s}^{-1}},-5\,m{{s}^{-2}} $
  • $ 19\,m{{s}^{-1}},-9\,m{{s}^{-2}} $
  • $ -14\,m{{s}^{-1}},-5\,m{{s}^{-2}} $
  • $ 5m{{s}^{-1}},14m{{s}^{-2}} $
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The Correct Option is D

Solution and Explanation

Rate of change of position is known as velocity and rate of change of velocity is known as acceleration.
Given $ y=3+5t+7{{t}^{2}} $
Velocity $ (v) $ is defined as rate of change of displacement, also using
$ \frac{d}{dx}{{x}^{n}}=n{{x}^{n-1}}, $
we have $ \therefore $ $ v=\frac{dy}{dt}=5+14\,t $
Initial velocity at $ t=0, $ is $ v=5\,m/s. $
Also acceleration $ a=\frac{{{d}^{2}}y}{d{{t}^{2}}}=14\,m/{{s}^{2}} $
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Concepts Used:

Acceleration

In the real world, everything is always in motion. Objects move at a variable or a constant speed. When someone steps on the accelerator or applies brakes on a car, the speed of the car increases or decreases and the direction of the car changes. In physics, these changes in velocity or directional magnitude of a moving object are represented by acceleration

acceleration