Question:
A particle is moving such that its position coordinates (x, y) are
(2m, 3m) at time t = 0,
(6m, 7m) at time t=2s and
(13m, 14m) at time t=5s.
Average velocity vector \((\overrightarrow{V}_{av})\) from t=0 to t=5s is:
A particle is moving such that its position coordinates (x, y) are
(2m, 3m) at time t = 0,
(6m, 7m) at time t=2s and
(13m, 14m) at time t=5s.
Average velocity vector \((\overrightarrow{V}_{av})\) from t=0 to t=5s is:
(2m, 3m) at time t = 0,
(6m, 7m) at time t=2s and
(13m, 14m) at time t=5s.
Average velocity vector \((\overrightarrow{V}_{av})\) from t=0 to t=5s is:
Updated On: May 22, 2024
- \(\frac{7}{3}(\hat{i}+\hat{j})\)
- \(2(\hat{i}+\hat{j})\)
- \(\frac{11}{5}(\hat{i}+\hat{j})\)
- \(\frac{1}{5}(13\hat{i}+14\hat{j})\)
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The Correct Option is C
Solution and Explanation
The correct option (C): \(\frac{11}{5}(\hat{i}+\hat{j})\)
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