A particle is having uniform acceleration. If its displacement from t to \((t + 1)\) second is \(120 \) \(m\) and change in velocity is \(50 \;m/s\). Find its displacement (in m) in \((t + 2)^{th}\) second
Solution and Explanation
\(\text{Displacement will be:}\)
\(a=50\;m/s^2\)
\(120=u+\frac{a}{2}(2(t+1)-1)\)
\(u=120-25(2t+1)\)
\(s'=u+\frac{a}{2}(2(t+2)-1)\)
\(=u+25(2t+3)\)
The Correct Answer is : \(170\)
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