\(\text{Displacement will be:}\)
\(a=50\;m/s^2\)
\(120=u+\frac{a}{2}(2(t+1)-1)\)
\(u=120-25(2t+1)\)
\(s'=u+\frac{a}{2}(2(t+2)-1)\)
\(=u+25(2t+3)\)
The Correct Answer is : \(170\)
The acceleration due to gravity at a height of 6400 km from the surface of the earth is \(2.5 \, \text{ms}^{-2}\). The acceleration due to gravity at a height of 12800 km from the surface of the earth is (Radius of the earth = 6400 km)
In the real world, everything is always in motion. Objects move at a variable or a constant speed. When someone steps on the accelerator or applies brakes on a car, the speed of the car increases or decreases and the direction of the car changes. In physics, these changes in velocity or directional magnitude of a moving object are represented by acceleration.