Question:
A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance $s_1$ in the first 10 seconds and distance $s_2$ in the next 10 seconds, then
A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance $s_1$ in the first 10 seconds and distance $s_2$ in the next 10 seconds, then
Updated On: Jul 5, 2022
- $s_2$ = $s_1$
- $s_2$ = $2 s_1$
- $s_2$ = $3 s_1$
- $s_2$ = $4 s_1$
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The Correct Option is C
Solution and Explanation
Let a be the constant acceleration of the particle.
Then $s = ut + \frac{1}{2} at^2$
or $s_1 = 0 + \frac{1}{2} \times a \times (10)^2 = 50 a$
and $s_2 = \left[ 0 + \frac{1}{2} a (20)^2\right] - 50a = 150 a $
$\therefore \, s_2 = 3s_1$
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Concepts Used:
Motion in a straight line
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Types of Linear Motion:
Linear motion is also known as the Rectilinear Motion which are of two types:
- Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
- Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.