Question

A parallel plate capacitor with a dielectric medium of dielectric constant 1.5 has a capacitance of \(C\). If the dielectric is removed, then the capacitance of the capacitor becomes

• A. \(\frac{3}{2} C\)
• B. \(\frac{1}{3} C\)
• C. \(\frac{2}{3} C\)
• D. \(C\)
• E. \(\frac{C}{2}\)
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Hint:

Remember, the capacitance with a dielectric is directly proportional to the dielectric constant.

Answer 1

The Correct Option is C

Step 1: The capacitance of a capacitor with a dielectric is given by \(C' = kC\), where \(k\) is the dielectric constant.
Step 2: With the dielectric, the capacitance is \(C = 1.5C_0\), where \(C_0\) is the original capacitance without the dielectric.
Step 3: Removing the dielectric, the capacitance returns to \(C_0\). Thus, \(C_0 = \frac{2}{3}C\).
Step 4: Therefore, the new capacitance is \(\frac{2}{3}C\). \bigskip