Step 1: Recall the Concept of Displacement Current
Displacement current is given by:
$$ I_d = \epsilon_0 \frac{d\Phi_E}{dt} $$
Where:
\( I_d \) = Displacement current
\( \epsilon_0 \) = Permittivity of free space
\( \Phi_E \) = Electric flux
\( t \) = Time
Step 2: Relate to Conduction Current
In a capacitor circuit, the displacement current in the gap is equal in magnitude to the conduction current in the connecting wires. This ensures continuity of current in the circuit.
Step 3: Conclusion
The displacement current flows in the same direction as the conduction current and has the same magnitude.
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :
A full wave rectifier circuit with diodes (\(D_1\)) and (\(D_2\)) is shown in the figure. If input supply voltage \(V_{in} = 220 \sin(100 \pi t)\) volt, then at \(t = 15\) msec:
A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of the circuit is :