Let:
\( P(L) = 0.7 \) → Probability of lockdown
\( P(\overline{L}) = 1 - 0.7 = 0.3 \) → No lockdown
\( P(C|L) = 0.8 \) → Probability that pandemic is controlled in one month given lockdown
\( P(C|\overline{L}) = 0.3 \) → Probability that pandemic is controlled in one month given no lockdown
Using the law of total probability:
\[ P(C) = P(L) \cdot P(C|L) + P(\overline{L}) \cdot P(C|\overline{L}) \] \[ P(C) = (0.7)(0.8) + (0.3)(0.3) = 0.56 + 0.09 = 0.65 \] Correct Answer: 0.65
Let L be the event that there will be a lockdown.
Let C be the event that the pandemic is controlled in one month.
We are given the following probabilities:
We want to find the probability that the pandemic will be controlled in one month, which is \(P(C)\).
We can use the Law of Total Probability. The event C can occur in two mutually exclusive ways: either there is a lockdown and the pandemic is controlled (\(C \cap L\)), or there is no lockdown and the pandemic is controlled (\(C \cap L'\)).
\[ P(C) = P(C \cap L) + P(C \cap L') \]
Using the definition of conditional probability, \(P(C \cap L) = P(C|L)P(L)\) and \(P(C \cap L') = P(C|L')P(L')\).
So, the formula becomes:
\[ \mathbf{P(C) = P(C|L)P(L) + P(C|L')P(L')} \]
Substitute the given values into the formula:
\[ P(C) = (0.8)(0.7) + (0.3)(0.3) \]
\[ P(C) = 0.56 + 0.09 \]
\[ P(C) = \mathbf{0.65} \]
The probability that the pandemic will be controlled in one month is 0.65.
Comparing this with the given options, the correct option is:
0.65
A shop selling electronic items sells smartphones of only three reputed companies A, B, and C because chances of their manufacturing a defective smartphone are only 5%, 4%, and 2% respectively. In his inventory, he has 25% smartphones from company A, 35% smartphones from company B, and 40% smartphones from company C.
A person buys a smartphone from this shop
A shop selling electronic items sells smartphones of only three reputed companies A, B, and C because chances of their manufacturing a defective smartphone are only 5%, 4%, and 2% respectively. In his inventory, he has 25% smartphones from company A, 35% smartphones from company B, and 40% smartphones from company C.
A person buys a smartphone from this shop
(i) Find the probability that it was defective.