Question:
A pale blue liquid obtained by equimolar mixture of two gases at $- 30^\circ\, C$ is
A pale blue liquid obtained by equimolar mixture of two gases at $- 30^\circ\, C$ is
Updated On: Jun 14, 2022
- $N_2O$
- $N_2O_3$
- $N_2O_4$
- $N_2O_5$
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The Correct Option is B
Solution and Explanation
Equimolar amounts of NO and $NO_2\, at\, -30^\circ\, C$ gives
$N_2O_3(/) $which is a blue liquid.
$NO(g) + NO_2(g)\xrightarrow{-30^\circ\, C}\, ^{N_2O_3(l)}_{(Blue)}$
$N_2O_3(/) $which is a blue liquid.
$NO(g) + NO_2(g)\xrightarrow{-30^\circ\, C}\, ^{N_2O_3(l)}_{(Blue)}$
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family