A → P is a zero-order reaction. At 298 K, the rate constant of the reaction is \( 1 \times 10^{-3} \) mol L\(^{-1}\) s\(^{-1}\).
Initial concentration of 'A' is 0.1 mol L\(^{-1}\). What is the concentration of 'A' after 10 sec?
Show Hint
For a zero-order reaction, the concentration decreases linearly with time:
\[
[A] = [A]_0 - k t
\]
Step 1: Zero-Order Reaction Formula
For a zero-order reaction, the concentration at time \( t \) is given by:
\[
[A] = [A]_0 - k t
\]
Step 2: Substituting the Given Values
\[
[A] = 0.1 - (1 \times 10^{-3} \times 10)
\]
\[
[A] = 0.1 - 0.01 = 0.09 { mol L}^{-1}
\]
Thus, the correct answer is 0.09 mol L\(^{-1}\).