Let the number be \( N \).
When divided by 195, the remainder is 47, so we can write:
\[
N = 195k + 47
\]
for some integer \( k \).
Now, divide \( N \) by 15:
\[
N = 195k + 47
\]
Dividing by 15:
\[
195k + 47 \quad \Rightarrow \quad \left( \frac{195k}{15} + \frac{47}{15} \right)
\]
Since \( \frac{195k}{15} \) is divisible by 15, we are left with the remainder from \( \frac{47}{15} \).
\[
47 \div 15 = 3 \text{ remainder } 2
\]
Thus, the remainder is \( \boxed{2} \).