A NOR gate has two input I1 and l2,and one output terminal Y. Which of the following configuration (truth table) is INCORRECT for the NOR gate?
I1=0,I2=0,Y=1
I1=0,I2=0,Y=0
I1=1,I2=1,Y=0
I1=1,I2=0,Y=0
I1=0,I2=1,Y=0
Given:
Step 1: Recall NOR Gate Logic
A NOR gate outputs 1 only when both inputs are 0. For all other input combinations, the output is 0.
Step 2: Evaluate Each Option
(A) \( I_1 = 0, I_2 = 0, Y = 1 \) → Correct (NOR output for 0,0).
(B) \( I_1 = 0, I_2 = 0, Y = 0 \) → Incorrect (should be 1).
(C) \( I_1 = 1, I_2 = 1, Y = 0 \) → Correct (NOR output for 1,1).
(D) \( I_1 = 1, I_2 = 0, Y = 0 \) → Correct (NOR output for 1,0).
(E) \( I_1 = 0, I_2 = 1, Y = 0 \) → Correct (NOR output for 0,1).
Conclusion:
The incorrect configuration is (B).
1. Understand the NOR gate:
A NOR gate gives an output of 1 (HIGH) only when both inputs are 0 (LOW). Otherwise, the output is 0 (LOW).
2. Analyze the truth table configurations:
Final Answer: The incorrect configuration is \(\boxed{B}\)
If \( 2 \) is a solution of the inequality \( \frac{x-a}{a-2x}<-3 \), then \( a \) must lie in the interval:
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