To solve the problem, we need to determine the speed of the motor boat in still water. Let's denote:
- \(v_b\): Speed of the boat in still water (in km/hr)
- \(v_s\): Speed of the stream (in km/hr)
In downstream, the effective speed of the boat is \(v_b+v_s\), and it covers 36 km. Time is given as 6 hours, so we can write the equation:
\(v_b+v_s=\frac{36}{6}=6 \text{ km/hr}\)
In upstream, the effective speed of the boat is \(v_b-v_s\), and it covers 24 km. Time is also given as 6 hours, so we can write:
\(v_b-v_s=\frac{24}{6}=4 \text{ km/hr}\)
We have two equations:
- \(v_b+v_s=6\)
- \(v_b-v_s=4\)
By adding these two equations, we eliminate \(v_s\):
\((v_b+v_s)+(v_b-v_s)=6+4\)
\(2v_b=10\)
Solving for \(v_b\), we get:
\(v_b=\frac{10}{2}=5 \text{ km/hr}\)
The speed of the motor boat in still water is 5 km/hr, which corresponds to the correct answer option.