Question:
A molecule AX$_2$ has two lone pairs over A. Its shape is
A molecule AX$_2$ has two lone pairs over A. Its shape is
Show Hint
Electron pair geometry may differ from molecular shape—lone pairs repel more strongly and change the shape.
Updated On: Jan 14, 2026
- Tetrahedral
- Pyramidal
- Angular
- Linear
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Step 1: Identify the number of electron pairs around the central atom A.
AX$_2$ with two lone pairs means:
\[
\text{Bond pairs} = 2,\quad \text{Lone pairs} = 2
\]
Step 2: Total electron pairs around A: \[ 2 + 2 = 4 \]
Step 3: According to VSEPR theory, 4 electron pairs give a tetrahedral electron pair geometry.
Step 4: However, the molecular shape depends only on the positions of bonded atoms, not lone pairs.
Step 5: With two bonded atoms and two lone pairs, the shape becomes bent or angular.
Step 6: Therefore, the correct shape is Angular.
Step 2: Total electron pairs around A: \[ 2 + 2 = 4 \]
Step 3: According to VSEPR theory, 4 electron pairs give a tetrahedral electron pair geometry.
Step 4: However, the molecular shape depends only on the positions of bonded atoms, not lone pairs.
Step 5: With two bonded atoms and two lone pairs, the shape becomes bent or angular.
Step 6: Therefore, the correct shape is Angular.
Was this answer helpful?
0
0
Top Questions on Chemical Kinetics
- For a reaction at $300 \text{ K}$, on addition of catalyst, activation energy of reaction lowered by $10 \text{ kJ}$. Then calculate the value of $\log \frac{K_{\text{catalysed}}}{K_{\text{uncatalysed}}}$
- JEE Main - 2026
- Chemistry
- Chemical Kinetics
- The reactions \(A \xrightarrow{k_1} B\) and \(C \xrightarrow{k_2} D\) follow first order kinetics. At \(500\,\text{K}\), rate constants are \(k_1\) and \(k_2\) respectively, where \(k_2 = 2k_1\). Activation energies \(E_{a1}\) and \(E_{a2}\) are related as \(E_{a2} = \dfrac{E_{a1}}{2}\). The rate constant for the first reaction at \(300\,\text{K}\) is half of its value at \(500\,\text{K}\). Given: half-life of first reaction is \(2\) hrs at \(500\,\text{K}\). Find the value of \(10 \times (k_2)_{300\,\text{K}\). }
- JEE Main - 2026
- Chemistry
- Chemical Kinetics
- For the $1^{\text{st}}$ order decomposition reaction $\text{A} \to \text{P}$. The value of $\frac{t_{1/8}}{t_{1/10}} \times 10$ will be :-
$t_{1/8} =$ time at which concentration of A become 1/8 of initial concentration.
$t_{1/10} =$ time at which concentration of A becomes 1/10 of initial concentration.- JEE Main - 2026
- Chemistry
- Chemical Kinetics
- Consider a first order reaction: \[ A \rightarrow \text{products} \] 3 different solutions are taken and the rate of reaction of: Solution 1: 100 mL 10M \( A \) \( \rightarrow r_1 \) Solution 2: 200 mL 10M \( A \) \( \rightarrow r_2 \) Solution 3: 100 mL 10M \( A \) + 100 mL water \( \rightarrow r_3 \) The correct order of the rates of reactions is,
- JEE Main - 2026
- Chemistry
- Chemical Kinetics
- For given zero order reaction AB $\longrightarrow$ A$_2$ + B$_2$, the graph is given for decomposition of [AB]. Find half-life (t$_{1/2}$) in minutes?
- JEE Main - 2026
- Chemistry
- Chemical Kinetics
View More Questions
Questions Asked in LPUNEST exam
- Identify the correctly spelled word.
- LPUNEST - 2026
- Vocabulary
- Which of the following solutions is the most acidic?
- LPUNEST - 2026
- Thermodynamics
- A train travels $120 \text{ km}$ in $2 \text{ hours}$. What is its speed?
- LPUNEST - 2026
- Sequences and Series
- If the cost price of an article is 500 and it is sold at a profit of $10%$, what is the selling price?
- LPUNEST - 2026
- Applications of Determinants and Matrices
- What is the simple interest on 2000 at $5%$ per annum for 2 years?
- LPUNEST - 2026
- Polynomials
View More Questions