Question:
A mixture of gases contains $H_2$ and $O_2$ gases in the ratio of 1 : 4 (w/w). What is the molar ratio of the two gases in the mixture?
A mixture of gases contains $H_2$ and $O_2$ gases in the ratio of 1 : 4 (w/w). What is the molar ratio of the two gases in the mixture?
Updated On: May 4, 2024
- 16 : 1
- 2 : 1
- 1 : 4
- 4 : 1
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The Correct Option is D
Solution and Explanation
The correct answer is D:\(4:1\)
A mixture of gases contains hydrogen \((H2)\) and oxygen \((O2)\) in a weight-to-weight ratio of \(1:4\). If we have \(100grams\) of hydrogen and \(400 grams\) of oxygen, we can calculate the number of moles for each gas based on their respective molar masses.
The number of moles of hydrogen present is: \(\frac{100 g}{2 g/mol} = 50 moles\).
The number of moles of oxygen present is \(\frac{400 g}{32 g/mol} = 12.5 moles.\)
\(\therefore\)The molar ratio of the two gases in the mixture is 50 moles of hydrogen to 12.5 moles of oxygen:\(\frac{50}{12.5}\); which simplifies to 4:1.
A mixture of gases contains hydrogen \((H2)\) and oxygen \((O2)\) in a weight-to-weight ratio of \(1:4\). If we have \(100grams\) of hydrogen and \(400 grams\) of oxygen, we can calculate the number of moles for each gas based on their respective molar masses.
The number of moles of hydrogen present is: \(\frac{100 g}{2 g/mol} = 50 moles\).
The number of moles of oxygen present is \(\frac{400 g}{32 g/mol} = 12.5 moles.\)
\(\therefore\)The molar ratio of the two gases in the mixture is 50 moles of hydrogen to 12.5 moles of oxygen:\(\frac{50}{12.5}\); which simplifies to 4:1.
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