Question:
A mixture of $CaCl_2$ and $NaCl$ weighing $4.44\, g$ is treated with sodium carbonate solution to precipitate all the calcium ions as calcium carbonate. The calcium carbonate so obtained is heated strongly to get $0.56\, g$ of $CaO$. The percentage of $NaCl$ in the mixture is
(Atomic mass of $Ca = 40)$
A mixture of $CaCl_2$ and $NaCl$ weighing $4.44\, g$ is treated with sodium carbonate solution to precipitate all the calcium ions as calcium carbonate. The calcium carbonate so obtained is heated strongly to get $0.56\, g$ of $CaO$. The percentage of $NaCl$ in the mixture is
(Atomic mass of $Ca = 40)$
Updated On: Apr 13, 2024
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The Correct Option is B
Solution and Explanation
$\underset{1 mol}{CaCO _{3}} \stackrel{\Delta}{\longrightarrow} \underset{1 mol}{CaO} + CO _{2}$
$\underset{1mol}{CaCl _{2}}+ Na _{2}CO _{3} \longrightarrow \underset{1mol}{CaCO _{3}}+2 Na$
$1 mol CaO \cong 1 mol CaCl _{2}$
$\frac{0.56}{56} mol CaO \cong 0.01 mol CaCl _{2}$
$=0.01 \times 111\, g CaCl _{2}$
$=1.11\, g CaCl _{2}$
Thus, in the mixture, weight of
$NaCl =4.44- 1.11=3.33\, g$
$\therefore$ Percentage of $NaCl =\frac{3.33}{4.44} \times 100$
$=75 \%$
$\underset{1mol}{CaCl _{2}}+ Na _{2}CO _{3} \longrightarrow \underset{1mol}{CaCO _{3}}+2 Na$
$1 mol CaO \cong 1 mol CaCl _{2}$
$\frac{0.56}{56} mol CaO \cong 0.01 mol CaCl _{2}$
$=0.01 \times 111\, g CaCl _{2}$
$=1.11\, g CaCl _{2}$
Thus, in the mixture, weight of
$NaCl =4.44- 1.11=3.33\, g$
$\therefore$ Percentage of $NaCl =\frac{3.33}{4.44} \times 100$
$=75 \%$
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Concepts Used:
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Chemistry is a vast subject and for understanding its significance we can take help of following points:
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- Chemistry is important in order to understand the behaviour of fertilizers, alkenes, acids, salts, dyes, polymers, drugs, soaps and alloys in organic and inorganic chemistry.
- Chemistry plays an important role in various fields like healthcare, industrial, research, food, and farm activities.
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Classification of Matter
There are two ways of classifying the matter:
(A) Physical Classification:
Matter can exist in three physical states:
- Solids - have definite volume and definite shape
- Liquids - have definite volume but not definite shape.
- Gases - have neither definite volume nor definite shape.
(B) Chemical Classification:
Based upon the composition, matter can be divided into two main types:
- Pure Substances are defined as a single substance (or matter) which cannot be separated by simple physical methods. Pure substances can be further classified as (i) Elements (ii) Compounds
- Mixtures are the combination of two or more elements or compounds which are not chemically combined together and may also be present in any proportion.