Question:

A microammeter has a resistance of 100Ω100 \Omega and full scale range of 50μA50 \mu A. It can be used as a voltmeter or as a higher range ammeter provided a resistance is added to it. Pick the correct range and resistance combination (s)

Updated On: Jun 23, 2023
  • 50 V range with 10kΩ10 k \Omega resistance in series
  • 10 V range with 2000kΩ2000 k \Omega resistance in series
  • 5 mA range with 1Ω1 \Omega resistance in parallel
  • 10 mA range with 1Ω1 \Omega resistance in parallel
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The Correct Option is C

Solution and Explanation

To increase the range of ammeter a parallel resistance (cal led shunt) is required which is given by
            S=(igiig)G \, \, \, \, \, \, \, \, \, \, \, \, S = \bigg( \frac{i_g}{i - i_g} \bigg)G
For option (c)
          S=(50×10650×10350×106)(100)1Ω \, \, \, \, \, \, \, \, \, \, S = \bigg( \frac{ 50 \times 10^{-6}}{50 \times 10^{-3} - 50 \times 10^{-6}} \bigg) (100) \approx 1 \Omega
To change it in voltmeter, a high resistance R is put in series,
where R is given by r=VigG r = \frac{V}{i_g} - G
For option (b), R=1050×106100200kΩR = \frac{10}{50 \times 10^{-6}} - 100 \approx 200k \Omega
Therefore, options (b) and (c) are correct.
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