Question:
A metallic conductor of length 1 m rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity 5 rad s–1. If the horizontal component of earth’s magnetic field is 0.2 × 10–4 T, then emf induced between the two ends of the conductor is:
A metallic conductor of length 1 m rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity 5 rad s–1. If the horizontal component of earth’s magnetic field is 0.2 × 10–4 T, then emf induced between the two ends of the conductor is:
Updated On: Feb 2, 2026
- 5 μV
- 50 μV
- 5 mV
- 50 mV
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The Correct Option is B
Solution and Explanation
Emf = \((\frac{1}{2})\)Bωl2
= \((\frac{1}{2})\)× 0.2 × 10–4 × 5 × 12 V
= 0.5 × 10–4 V
= 50 μV
\(\therefore, \) The correct answer is (B): 50 μV
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Concepts Used:
Electromagnetic Induction
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Formula:
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Where
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Applications of Electromagnetic Induction
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