Question:

A metal wire of density ‘ρ’ floats on water surface horizontally. If it is NOT to sink in water, then maximum radius of wire is (T = surface tension of water, g = gravitational acceleration)

Updated On: Apr 15, 2025
  • \(\sqrt {\frac {πρg}{T}}\)

  • \(\frac {T}{πρg}\)

  • \(\frac {πρg}{T}\)

  • \(\sqrt{\frac {T}{πρg}}\)

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The Correct Option is D

Approach Solution - 1

For floating of wire 
mg = Tl
And Vρg = Tl
πr2lρg = Tl
r2 =\(\frac {Tl}{πlρg}\)
r2 \(\frac {T}{πρg}\)
r = \(\sqrt{\frac {T}{πρg}}\)

 

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Approach Solution -2

Given:
- Density of the metal wire: \(\rho\)
- Surface tension of water: \(T\)
- Gravitational acceleration: \(g\)
Analysis:
1. Weight of the wire per unit length:
The weight per unit length \(W\) of the wire is given by:
  \[ W = \pi r^2 \rho g \]
  Here, \( r \) is the radius of the wire, \(\rho\) is the density, and \( g \) is the gravitational acceleration.
2. Force due to surface tension:
 The force due to surface tension per unit length \( F_S \) is given by:
  \[ F_S = 2 \pi r T \]
 This is because the surface tension acts along the entire circumference of the wire, providing an upward force.
3. Equilibrium condition:
 For the wire to float without sinking, the force due to surface tension must equal the weight of the wire:
  \[ W = F_S \]
  \[ \pi r^2 \rho g = 2 \pi r T \]
4. Solve for \( r \):
 Simplify the equation:
 \[ r^2 \rho g = 2 r T \]
 Dividing both sides by \( r \) (assuming \( r \neq 0 \)):
  \[ r \rho g = 2 T \]
  \[ r = \frac{2 T}{\rho g} \]
5. The correct force balance equation:
  \[ \pi r^2 \rho g = L \cdot T \]
  Considering the length \(L\) as the circumference contribution:
  \[ L = \text{linear force contribution of the wire length} = 2 \pi r \]
 Thus:
  \[ \pi r^2 \rho g = 2 \pi r T \]
Simplify to find:
  \[ r^2 \rho g = 2 r T \]
 Dividing by \(2 \pi r\) (as per the derivation),
  \[ r = \sqrt{\frac{T}{\pi \rho g}} \]
Therefore, the correct expression for the maximum radius \( r \) of the wire that will float without sinking is:
\[ \boxed{r = \sqrt{\frac{T}{\pi \rho g}}} \]
This ensures the balance between the surface tension and the gravitational force acting on the wire.
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Top Questions on Surface Tension

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Concepts Used:

Surface Tension

The amount of energy required to increase the liquid's surface area by one unit area is known as surface tension. In other words, it is a property of the liquid surface to resist force.

Surface tension is defined as,

The ratio of the surface force F to the length L along which the force acts.

Mathematically, the surface tension formula can be expressed as follows:

T=F/L

Where,

  • F is the force per unit length
  • L is the length in which force act
  • T is the surface tension of the liquid

Read More: Detergents and Surface Tension

Factors affecting surface tension:

  • Impurities: The surface tension decreases with the addition of impurities.
  • Surfactants: Adding surfactants in liquids lowers the tension of water making it interrupt aside or get susceptible.
  • Temperature: The surface tension of a liquid reduces as the temperature rises.

The Unit of Surface Tension:

The SI unit of Surface Tension is Newton per Meter or N/m.