To solve this problem, we need to determine the number of matrices R, given that R = αP, where P is a matrix with each entry either 0 or 1, and α is a scalar which is either 3 or 4.
First, consider the matrix P, which is of order 2 × 3, meaning it has 2 rows and 3 columns, hence a total of 6 elements. Each element in P can independently be 0 or 1. This gives:
Number of possible P matrices = 26 = 64.
For each matrix P, scalar multiplication by α = 3 or 4 will give a unique matrix R. Each element in P, which is either 0 or 1, when multiplied by α, remains either 0 (if the element was 0) or will be α (if the element was 1). Therefore, the multiplication does not change the number of distinct matrices that can be formed. Hence, changing α will not affect the count of the unique transformations from matrix P to matrix R.
Therefore, the total number of matrices R that can be formed is equal exactly to the number of matrices P.
Thus, the number of matrices R formed is 64.