Step 1: Understanding the Problem
Let the speed of the boat in still water be \( b \) km/hr and the speed of the river current be \( c \) km/hr.
When the boat is rowing downstream, the effective speed of the boat is \( b + c \).
When the boat is rowing upstream, the effective speed of the boat is \( b - c \).
Step 2: Calculating Downstream and Upstream Speeds
Downstream: The man covers 15 km in 3 hours 45 minutes (which is \( 3.75 \) hours).
So, the effective downstream speed is:
\[
\text{Speed downstream} = \frac{15}{3.75} = 4 \, \text{km/hr}
\]
Hence, \( b + c = 4 \).
Upstream: The man covers 5 km in 2 hours 30 minutes (which is \( 2.5 \) hours).
So, the effective upstream speed is:
\[
\text{Speed upstream} = \frac{5}{2.5} = 2 \, \text{km/hr}
\]
Hence, \( b - c = 2 \).
Step 3: Solving the System of Equations
We now have the following system of equations:
\[
b + c = 4
b - c = 2
\]
Adding these two equations:
\[
(b + c) + (b - c) = 4 + 2
2b = 6
b = 3
\]
Substitute \( b = 3 \) into either equation, say \( b + c = 4 \):
\[
3 + c = 4
c = 1
\]
Thus, the speed of the river current is \( c = 1 \, \text{km/hr} \).
Therefore, the correct answer is (2) 1.