Question:
A man slides down a light rope whose breaking strength is $ \eta $ times his weight. What should be his maximum acceleration so that the rope just not breaks?
A man slides down a light rope whose breaking strength is $ \eta $ times his weight. What should be his maximum acceleration so that the rope just not breaks?
Updated On: Aug 15, 2022
- $ g(1-\eta ) $
- $ \eta g $
- $ \frac{g}{1+\eta } $
- $ \frac{g}{1-\eta } $
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The Correct Option is A
Solution and Explanation
$ mg-R=ma $
$ mg=\eta mg=ma $
$ [\because \,R=\eta \,mg] $
$ mg(1-\eta )=ma $
$ a=g(1-\eta ) $
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Concepts Used:
Gravitation
In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.
Newton’s Law of Gravitation
According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,
- F ∝ (M1M2) . . . . (1)
- (F ∝ 1/r2) . . . . (2)
On combining equations (1) and (2) we get,
F ∝ M1M2/r2
F = G × [M1M2]/r2 . . . . (7)
Or, f(r) = GM1M2/r2
The dimension formula of G is [M-1L3T-2].