A man sells 10 oranges for a rupee there by gaining 40%. How many oranges did he buy for a rupee?
- 12
- 14
- 13
- 15
- 11
The Correct Option is A
Solution and Explanation
Top Questions on Profit and Loss
- An iron beam made with rare materials has its market price dependent on the square of its length. The beam broke into two pieces in the ratio of 4 : 9. If it is sold as two separate pieces, what would be the percentage profit or loss compared to its original value?
- Ankit and Raju decided to start a business and they invested Rs. 5500 and Rs. 6500 respectively. After 11 months, the difference between their profits is Rs. 680. Find the total profit.
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- General Aptitude
- Profit and Loss
- A certain sum becomes 2356 in 3 years and 2660 in 5 years on simple interest. What is the value of the sum?
- CUET (UG) - 2024
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- An item is sold for 504 after allowing a 20% discount. If the shopkeeper gains 5%, then the cost price of the item is:
- CUET (UG) - 2024
- General Aptitude
- Profit and Loss
A furniture trader deals in tables and chairs. He has Rs. 75,000 to invest and a space to store at most 60 items. A table costs him Rs. 1,500 and a chair costs him Rs. 1,000. The trader earns a profit of Rs. 400 and Rs. 250 on a table and chair, respectively. Assuming that he can sell all the items that he can buy, which of the following is/are true for the above problem:
(A) Let the trader buy \( x \) tables and \( y \) chairs. Let \( Z \) denote the total profit. Thus, the mathematical formulation of the given problem is:
\[ Z = 400x + 250y, \]
subject to constraints:
\[ x + y \leq 60, \quad 3x + 2y \leq 150, \quad x \geq 0, \quad y \geq 0. \]
(B) The corner points of the feasible region are (0, 0), (50, 0), (30, 30), and (0, 60).
(C) Maximum profit is Rs. 19,500 when trader purchases 60 chairs only.
(D) Maximum profit is Rs. 20,000 when trader purchases 50 tables only.
Choose the correct answer from the options given below:
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- Mathematics
- Profit and Loss
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