Question:
A man, of mass $60\, kg$, is riding in a lift. The weight of the man, when the lift is accelerating upwards and downwards at $2\, ms ^{-2}$ are respectively (taking $g=10\, ms ^{-2}$ )
A man, of mass $60\, kg$, is riding in a lift. The weight of the man, when the lift is accelerating upwards and downwards at $2\, ms ^{-2}$ are respectively (taking $g=10\, ms ^{-2}$ )
Updated On: Jan 18, 2023
- 720 N and 480 N
- 480 N and 720 N
- 600 N and 600 N
- None of these
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The Correct Option is A
Solution and Explanation
When the lift is accelerating upwards with constant acceleration $a$,
then Weight $w=m(g+ a)$
$=60(10+2)=60 \times 12=720\, N$
When the lift is accelerating downwards at the rate of $a$,
then Weight $w=m(g-a)$
$=60(10-2)=60 \times 8=480\, N$
then Weight $w=m(g+ a)$
$=60(10+2)=60 \times 12=720\, N$
When the lift is accelerating downwards at the rate of $a$,
then Weight $w=m(g-a)$
$=60(10-2)=60 \times 8=480\, N$
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Concepts Used:
Acceleration
In the real world, everything is always in motion. Objects move at a variable or a constant speed. When someone steps on the accelerator or applies brakes on a car, the speed of the car increases or decreases and the direction of the car changes. In physics, these changes in velocity or directional magnitude of a moving object are represented by acceleration.
