To solve the problem, we need to determine the volume and number of cylinders that can be made from each type of metal and ensure that they are minimized. Each cylinder has a radius \( r = 3 \) cm. The formula for the volume of a cylinder is \( V = \pi r^2 h \). Given:
The cylinders have equal volumes, thus the height \( h \) is the same for all metals. Setting the volume formula equal to each metal volume yields:
We get:
We need a common height to ensure each cylinder has the same volume across different metals. Find the GCD of the volumes for determining the minimum number of cylinders:
So, the volume of each cylinder = \(27\) cc. Find total number of cylinders:
Each cylinder has radius \( r = 3 \) cm, height = \( \frac{27}{9\pi} = \frac{3}{\pi} \). Calculate the surface area of a cylinder:
Thus, the total surface area for all cylinders is:
This results in the total surface area being \(1026(1+\pi)\) square cm, making it the correct option.
On the day of her examination, Riya sharpened her pencil from both ends as shown below. 
The diameter of the cylindrical and conical part of the pencil is 4.2 mm. If the height of each conical part is 2.8 mm and the length of the entire pencil is 105.6 mm, find the total surface area of the pencil.
Two identical cones are joined as shown in the figure. If radius of base is 4 cm and slant height of the cone is 6 cm, then height of the solid is
From one face of a solid cube of side 14 cm, the largest possible cone is carved out. Find the volume and surface area of the remaining solid.
Use $\pi = \dfrac{22}{7}, \sqrt{5} = 2.2$
The radius of a circle with centre 'P' is 10 cm. If chord AB of the circle subtends a right angle at P, find area of minor sector by using the following activity. (\(\pi = 3.14\)) 
Activity :
r = 10 cm, \(\theta\) = 90\(^\circ\), \(\pi\) = 3.14.
A(P-AXB) = \(\frac{\theta}{360} \times \boxed{\phantom{\pi r^2}}\) = \(\frac{\boxed{\phantom{90}}}{360} \times 3.14 \times 10^2\) = \(\frac{1}{4} \times \boxed{\phantom{314}}\) <br>
A(P-AXB) = \(\boxed{\phantom{78.5}}\) sq. cm.