To solve the problem, we need to determine the volume and number of cylinders that can be made from each type of metal and ensure that they are minimized. Each cylinder has a radius \( r = 3 \) cm. The formula for the volume of a cylinder is \( V = \pi r^2 h \). Given:
The cylinders have equal volumes, thus the height \( h \) is the same for all metals. Setting the volume formula equal to each metal volume yields:
We get:
We need a common height to ensure each cylinder has the same volume across different metals. Find the GCD of the volumes for determining the minimum number of cylinders:
So, the volume of each cylinder = \(27\) cc. Find total number of cylinders:
Each cylinder has radius \( r = 3 \) cm, height = \( \frac{27}{9\pi} = \frac{3}{\pi} \). Calculate the surface area of a cylinder:
Thus, the total surface area for all cylinders is:
This results in the total surface area being \(1026(1+\pi)\) square cm, making it the correct option.
From one face of a solid cube of side 14 cm, the largest possible cone is carved out. Find the volume and surface area of the remaining solid.
Use $\pi = \dfrac{22}{7}, \sqrt{5} = 2.2$