The problem involves the man laying stones on both sides of a 200-meter walkway, with stones placed 5 meters apart. He places two stones at the start and continues with the remaining stones alternating between the two sides of the path.
To calculate the total distance he walks, follow these steps:
Since stones are placed every 5 meters along a 200-meter path, the number of stones required per side is: 200/5+1=41
Multiply by 2 because there are two sides: 41×2=82
1. The first stone is placed at the starting point (no walking needed).
2. He walks to place stones from 5m to 200m and returns after each placement.
3. Calculate distances walked:
lwalk=2(5+10+…+195+200)
Arithmetic sequence sum calculation:Sum=n2(a+l)=402(5+200)=20×205=4100
Total walking distance for one side
2×4100=8200
Finally, after laying down all the stones, the man returns to the start, an additional 200m, adding to: 8200+8200+200=16400 meters walked.
If the equation \( a(b - c)x^2 + b(c - a)x + c(a - b) = 0 \) has equal roots, where \( a + c = 15 \) and \( b = \frac{36}{5} \), then \( a^2 + c^2 \) is equal to .
Match the following authors with their respective works.
Authors | Books |
---|---|
1. Andy Weir | A. Dune |
2. Cixin Liu | B. The Time Machine |
3. Stephen Hawking | C. The Brief History of Time |
4. HG Wells | D. The Martian |
5. Frank Herbert | E. The Three Body Problem |