Question:

A magnetic moment of 1.73 BM will be shown by one among the following :-

Updated On: June 02, 2025
  • $[CoCl_6]^{4-}$
  • $[ Cu (NH_3)_4]^{2+}$
  • $[Ni(CN)_4]^{2-}$
  • $TiCl_4$
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The Correct Option is B

Solution and Explanation

Magnetic moment 1.73 BM
$\mu = \sqrt{n (n +2) } B.M$
n = no. of unpaired e-
$\mu = 1.73$
$ 1.73 = \sqrt{n ( n+2)} B.M$
$n = 1$
$* [CoCl_6]^{4-} \to Co^{+2} ; d^7$
Cl- (weak field ligand) $t_2g^5eg^2$ unpaired $e^-= 3$
$* [Cu(NH_3)_4]^{2+} Cu^{+2} - d^9$
$NH_3$ Strong field ligand, hybridisation $dsp^2$
$*$ one $e^-$ of $3d$
$* [Ni(CN)_4]^{2-} \to Ni^{+2} - d^8$ unpaired $e^- =0$
$CN^-$ - Strong field ligand $dsp^2$
$* TiCl_4 \to Ti^{+4} d^{\circ}$ unpaired e- = zero.
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Concepts Used:

Coordination Compounds

A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.

Coordination entity:

A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.

Ligands:

A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.