Question:
A long wire carrying current \(\sqrt{(2)}A\) is placed in a uniform magnetic field of \(3 \times 10^{-5}\; T\). If the magnetic field is perpendicular to wire, find magnetic force on the length of wire.
A long wire carrying current \(\sqrt{(2)}A\) is placed in a uniform magnetic field of \(3 \times 10^{-5}\; T\). If the magnetic field is perpendicular to wire, find magnetic force on the length of wire.
Updated On: Feb 2, 2026
- \(3 \times 10^{-4}\; N\)
- \(3\sqrt{(2)} \times 10^{-5} N\)
- \(3 \times 10^{-3}\; N\)
- Zero
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The Correct Option is B
Solution and Explanation
The Correct Option is (B): \(3\sqrt{(2)} \times 10^{-5} N\)
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Concepts Used:
Magnetic Field
The magnetic field is a field created by moving electric charges. It is a force field that exerts a force on materials such as iron when they are placed in its vicinity. Magnetic fields do not require a medium to propagate; they can even propagate in a vacuum. Magnetic field also referred to as a vector field, describes the magnetic influence on moving electric charges, magnetic materials, and electric currents.
A magnetic field can be presented in two ways.
- Magnetic Field Vector: The magnetic field is described mathematically as a vector field. This vector field can be plotted directly as a set of many vectors drawn on a grid. Each vector points in the direction that a compass would point and has length dependent on the strength of the magnetic force.
- Magnetic Field Lines: An alternative way to represent the information contained within a vector field is with the use of field lines. Here we dispense with the grid pattern and connect the vectors with smooth lines.
Properties of Magnetic Field Lines
- Magnetic field lines never cross each other
- The density of the field lines indicates the strength of the field
- Magnetic field lines always make closed-loops
- Magnetic field lines always emerge or start from the north pole and terminate at the south pole.