Step 1: Identify the intended symmetry axes.
For a $4 \times 5$ grid, the two natural symmetry lines are:
(i) a vertical line between columns 2 and 3, and
(ii) a horizontal line through the middle row (row 3).
Step 2: Check which existing blacks already satisfy symmetry.
- Horizontal symmetry pairs: $(r1,c2)\leftrightarrow(r5,c2)$, $(r1,c3)\leftrightarrow(r5,c3)$, $(r2,c1)\leftrightarrow(r4,c1)$, $(r2,c4)\leftrightarrow(r4,c4)$ are already black–black and hence fine.
- The mismatch for horizontal symmetry occurs at $(r4,c3)$ which is black; its mirror across row 3 is $(r2,c3)=d$ (currently white). Thus d must be coloured black.
Step 3: Enforce vertical symmetry (mirror across columns 2 and 3).
- Cell $(r4,c3)$ is black; its vertical mirror is $(r4,c2)=i$ (white). Hence i must be coloured black.
- With d black (from Step 2), its vertical mirror is $(r2,c2)=c$; therefore c must also be black for vertical symmetry.
Step 4: Minimality check.
Colouring c, d, and i makes all horizontal and vertical mirror pairs match. No other cells are required; choosing fewer (e.g., only c,i) fails the horizontal pair $(r2,c3)\leftrightarrow(r4,c3)$, and any extra cells (e.g., f,g) are unnecessary.
\[
\boxed{\text{Colour exactly } c, d, \text{ and } i \text{ to achieve two lines of symmetry (minimum = 3).}}
\]