Question

A Lewis acid 'X' formed by the reaction of BF3 with LiA/H₄ in ether medium to gives a highly toxic gas. This gas when heated with NH₃ gives a compound commonly known as inorganic benzene. The gas is

• A. BF₃
• B. B₂O₃
• C. B₂H₆
• D. B₂N₃H₆

Answer 1

The Correct Option is C

The reaction described in the question involves a Lewis acid that reacts with LiAlH_4 to give a highly toxic gas. The gas in question is diborane (\( \text{B}_2\text{H}_6 \)), which is a highly toxic and volatile compound. When diborane reacts with ammonia (\( \text{NH}_3 \)), it forms a compound commonly known as inorganic benzene. This compound is known as borazine, \( \text{B}_3\text{N}_3\text{H}_6 \), which has a structure similar to benzene, but with alternating boron and nitrogen atoms. Thus, the gas that reacts with NH_3 to form inorganic benzene is \( \text{B}_2\text{H}_6 \).

The correct option is(C): \(B_2H_6\)

Answer 2

The question describes a reaction involving a Lewis acid, LiAlH₄, and NH₃. The key clues are:
- The reaction produces a highly toxic gas, which points to diborane (B₂H₆), a toxic and unstable gas.
- When diborane reacts with ammonia (NH₃), it forms inorganic benzene, commonly referred to as borazine (B₃N₃H₆), which is a compound resembling benzene but containing boron and nitrogen atoms.

The reaction proceeds as follows:
\(B_2H_6 + 6NH_3 \rightarrow B_3N_3H_6 + 3H_2\)
This reaction is known to produce **borazine**, often called **inorganic benzene**.

Thus, the correct answer is (C) \( \text{B}_2\text{H}_6 \) (diborane).