A ladder leaning against a wall makes an angle of 45° with the ground. If the length of the ladder is 10 m, what is the distance of the foot of the ladder from the wall?
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Use basic trigonometric ratios in right-angled triangles to find distances related to angles and hypotenuse.
Let the ladder length = 10 m, angle with ground = 45°. We need to find the distance of foot of ladder from the wall, i.e., the base BC in right triangle ABC. Using trigonometric relation for the base: \[\cos 45^\circ = \frac{\text{Base}}{\text{Hypotenuse}} = \frac{BC}{10}\] \[BC = 10 \times \cos 45^\circ = 10 \times \frac{1}{\sqrt{2}} = \frac{10}{\sqrt{2}} = 5\sqrt{2} m\]