The apparent power \( S \) is given by:
\[
S = V_{\text{rms}} \times I_{\text{rms}} = 230 \times 0.3125 = 71.5 \, \text{VA}
\]
The real power \( P \) is given as 60 W. The reactive power \( Q \) can be calculated using the Pythagorean identity:
\[
S^2 = P^2 + Q^2
\]
Solving for \( Q \):
\[
Q^2 = S^2 - P^2 = 71.5^2 - 60^2 = 5112.25 - 3600 = 1512.25
\]
\[
Q = \sqrt{1512.25} \approx 38.9 \, \text{VAr}
\]
Rounding to the nearest integer:
\[
Q \approx 39 \, \text{VAr}
\]
Thus, the reactive power drawn by the fan is \( 39 \, \text{VAr} \).