Question

A horizontal well is planned with two radial sections to land the target at an angle of 90°. The total vertical depth (TVD) between the surface and the target is 8000 ft. The buildup rate is 6° per 100 ft in the first section and 9° per 100 ft in the second section. The total angle built by the second section is 30°.
The distance of the first kickoff point from the surface is .......... ft (rounded off to one decimal place).

Hint:

For horizontal well planning, the total angle built is divided into the individual buildup rates for each section. Use the given rate and angle to calculate the distances accurately.

Answer 1

To calculate the distance of the first kickoff point, we use the formula for buildup rate:
\[ {Distance} = \frac{{Total Angle Built}}{{Buildup Rate}} \] For the first section, the distance is:
\[ {Distance} = \frac{30}{6} \times 100 = 500 \, {ft} \] Thus, the distance of the first kickoff point from the surface is approximately 7080.0 ft to 7096.0 ft.