Question:

A horizontal force 10 N is applied to a block 4 as shown in figure. The mass of blocks A and B are 2 kg and 3 kg, respectively. The blocks slide over a frictionless surface. The force exerted by block A on block B is:

Updated On: Dec 4, 2024
  • Zero
  • \(4N\)
  • \(6N\)
  • \(10N\)
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The Correct Option is C

Solution and Explanation

The total acceleration of the system is:
$a = \frac{F}{m_A + m_B} = \frac{10}{2 + 3} = 2 \, m/s^2$.
The force exerted by A on B is:
$F_{AB} = m_B \cdot a = 3 \times 2 = 6 \, N$.

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