Step 1: Calculate the acceleration of the system.
The total mass of the system is: M = mA + mB = 2kg + 3kg = 5kg. - Using Newton’s second law:F=M⋅a⇒a=FM=105=2 m/s2F=M⋅a⇒a=MF=510=2 m/s2
Step 2:
Calculate the force exerted by block A on block B. - The force on block B due to block A is:FB=mB⋅a=3×2=6NFB=mB⋅a=3×2=6N
Step 3:
Conclude. - The force exerted by block A on block B is 6N.
Step 1: Calculate the acceleration of the system.
- The total mass of the system is: M = mA + mB = 2kg + 3kg = 5kg. - Using Newton’s second law: \[ F = M \cdot a \Rightarrow a = \frac{F}{M} = \frac{10}{5} = 2 \text{ m/s}^2 \] Step 2: Calculate the force exerted by block A on block B. - The force on block B due to block A is: \[ F_B = m_B \cdot a = 3 \times 2 = 6N \] Step 3: Conclude. - The force exerted by block A on block B is 6N.
In the given LCR series circuit the quality factor is
List I (Spectral Lines of Hydrogen for transitions from) | List II (Wavelength (nm)) | ||
A. | n2 = 3 to n1 = 2 | I. | 410.2 |
B. | n2 = 4 to n1 = 2 | II. | 434.1 |
C. | n2 = 5 to n1 = 2 | III. | 656.3 |
D. | n2 = 6 to n1 = 2 | IV. | 486.1 |
The following diagram shown restriction sites in E. coli cloning vector pBR322. Find the role of ‘X’ and ‘Y’gens :