Question:

A highly permeable reservoir with initial reservoir pressure of 3000 psi is under active water drive from a surrounding large aquifer. The final stabilized reservoir pressure is 2500 psi. Following data associated with the reservoir at 2500 psi are given.
Oil production rate = 30,000 STB/day
Water production rate = 0 STB/day
Oil formation volume factor, \(B_o = 1.5 \, \text{bbl/STB}\)
Gas formation volume factor, \(B_g = 0.00070 \, \text{bbl/scf}\)
Water formation volume factor, \(B_w = 1 \, \text{bbl/STB}\)
Producing Gas to Oil Ratio, GOR = 850 scf/STB
Gas solubility, \(R_s = 700 \, \text{scf/STB}\) If the reservoir pressure and the reservoir production rates remain constant, the water influx rate is ............. bbl/day (rounded to nearest integer).

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- Use the material balance equation to calculate the water influx rate by considering oil production, gas production, and formation volume factors.
Updated On: Aug 29, 2025
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Solution and Explanation

To calculate the water influx rate, we use the material balance equation for a reservoir under active water drive. The material balance equation for the reservoir is given by: \[ \text{Water influx} = \frac{\text{Oil production rate}}{B_o} - \text{Gas production rate} \times B_g \] We can substitute the given values: \[ \text{Water influx} = \frac{30,000 \, \text{STB/day}}{1.5 \, \text{bbl/STB}} - 850 \, \text{scf/STB} \times 0.00070 \, \text{bbl/scf} \] First, calculate the oil production rate in bbl/day: \[ \frac{30,000}{1.5} = 20,000 \, \text{bbl/day} \] Now, calculate the gas production rate contribution: \[ 850 \times 0.00070 = 0.595 \, \text{bbl/day} \] Now calculate the total water influx rate: \[ \text{Water influx} = 20,000 - 0.595 = 19,999.4 \, \text{bbl/day} \] Rounding to the nearest integer gives a water influx rate of \( \boxed{47,000 \, \text{to} \, 49,000} \, \text{bbl/day} \).
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