(a) \(H_2O_2 + O_3 → H_2O + 2O_2\)
(b) \(H_2O_2 + Ag_2O → 2Ag + H_2O + O_2\)
Role of hydrogen peroxide in the above reactions is respectively:
(b) \(H_2O_2 + Ag_2O → 2Ag + H_2O + O_2\)
Role of hydrogen peroxide in the above reactions is respectively:
- Reducing in (a) and oxidizing in (b)
- Reducing in (a) and (b)
- Oxidizing in (a) and (b)
- Oxidizing in (a) and reducing in (b)
The Correct Option is B
Solution and Explanation
Top Questions on p -Block Elements
Given below are two statements.
In the light of the above statements, choose the correct answer from the options given below:- JEE Main - 2025
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Given below are two statements:
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Statement II: Nitrogen does not form halides with +5 oxidation state due to the absence of d-orbital in it.
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Given below are the pairs of group 13 elements showing their relation in terms of atomic radius. $(\mathrm{B}<\mathrm{Al}),(\mathrm{Al}<\mathrm{Ga}),(\mathrm{Ga}<\mathrm{In})$ and $(\mathrm{In}<\mathrm{Tl})$ Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius $\left(\mathrm{M}^{3+}\right)$ than the other one. The atomic number of the element (X) is
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B. The reducing ability of the hydrides increases in the order \(\text{NH}_3 < \text{PH}_3 < \text{AsH}_3 < \text{SbH}_3 < \text{BiH}_3\)
C. Among the hydrides, \(\text{NH}_3\) is a strong reducing agent while \(\text{BiH}_3\) is a mild reducing agent.
D. The basicity of the hydrides increases in the order \(\text{NH}_3 < \text{PH}_3 < \text{AsH}_3 < \text{SbH}_3 < \text{BiH}_3\)
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