Initially, the glass is filled entirely with milk. We denote the initial amount of milk as \(M=1\). In the first step, \(\frac{2}{3}\) of the milk is replaced with water.
The remaining milk after step 1 is:
\(M_1=M-\frac{2}{3}M=\frac{1}{3}M\)
Water added = \(\frac{2}{3}\)
In the second step, \(\frac{2}{3}\) of the remaining milk is replaced with water:
Remaining milk after step 2:
\(M_2=\frac{1}{3}M_1=\frac{1}{3}\times\frac{1}{3}M=\frac{1}{9}M\)
Water added = \(\frac{2}{3}+\frac{2}{3}\times\frac{1}{3}=\frac{2}{3}+\frac{2}{9}=\frac{8}{9}\)
In the third step, \(\frac{2}{3}\) of the remaining milk is again replaced with water:
Remaining milk after step 3:
\(M_3=\frac{1}{3}M_2=\frac{1}{3}\times\frac{1}{9}M=\frac{1}{27}M\)
Water added = \(1-\frac{1}{27}=\frac{26}{27}\)
The final water to milk ratio is:
\(\frac{\frac{26}{27}}{\frac{1}{27}}=26:1\)
For any natural number $k$, let $a_k = 3^k$. The smallest natural number $m$ for which \[ (a_1)^1 \times (a_2)^2 \times \dots \times (a_{20})^{20} \;<\; a_{21} \times a_{22} \times \dots \times a_{20+m} \] is: