Initially:
Now we need to calculate how much milk and water are in that 150 cc mixture:
So the 150 cc taken back to the glass contains:
\[ \text{Milk in Glass} : \text{Water in Cup} = 384.62 : 384.62 = \boxed{1 : 1} \]
\[ \boxed{\text{Option (C): } 1 : 1} \]
You are given:
Two transfers are made:
What is the final ratio of water in the glass to milk in the cup?
Mixture in cup is 150 cc milk and 500 cc water → ratio \( 3:10 \).
So in 150 cc of this mixture:
Water in glass : Milk in cup \[ = 115.38 : 115.38 = \boxed{1 : 1} \]
\[ \boxed{\text{Option (C): } 1 : 1} \]
For any natural number $k$, let $a_k = 3^k$. The smallest natural number $m$ for which \[ (a_1)^1 \times (a_2)^2 \times \dots \times (a_{20})^{20} \;<\; a_{21} \times a_{22} \times \dots \times a_{20+m} \] is: