Question:

A given zone is characterized in the following tables in terms of household size, and vehicle ownership. Table I shows the trip rates of households, and Table II shows the household composition. For households of size two and above, having one or more vehicles, the total daily home-based trips made are \underline{\hspace{1cm}} [in integer].

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Always filter the households based on the exact conditions given (in this case, size ≥ 2 and vehicles ≥ 1). Multiply household numbers by trip rates, then sum for the final answer.
Updated On: Aug 30, 2025
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Solution and Explanation

Step 1: Interpret the problem.
We are asked to compute total daily home-based trips for: - Households with size two and above (i.e., 2 persons or 3+ persons). - Households with one or more vehicles (i.e., categories "One (1)" and "Two \& above (2+)"). We use Table I (trip rates per household) and Table II (number of households).

Step 2: Extract relevant values. From Table I – Trip rate of households: \[ \begin{array}{|c|c|c|} \hline \text{Vehicles/household} & \text{Two (2)} & \text{Three \& above (3+)}
\hline \text{One (1)} & 2.5 & 5
\text{Two \& above (2+)} & 3 & 6
\hline \end{array} \] From Table II – Household composition: \[ \begin{array}{|c|c|c|} \hline \text{Vehicles/household} & \text{Two (2)} & \text{Three \& above (3+)}
\hline \text{One (1)} & 300 & 200
\text{Two \& above (2+)} & 100 & 50
\hline \end{array} \]

Step 3: Compute trips = households × trip rate. \[ \text{Case 1: One vehicle, Two persons} = 300 \times 2.5 = 750 \] \[ \text{Case 2: One vehicle, Three+ persons} = 200 \times 5 = 1000 \] \[ \text{Case 3: Two+ vehicles, Two persons} = 100 \times 3 = 300 \] \[ \text{Case 4: Two+ vehicles, Three+ persons} = 50 \times 6 = 300 \]

Step 4: Add all contributions. \[ \text{Total Trips} = 750 + 1000 + 300 + 300 = 2350 \] Wait — let us double-check carefully.

Step 5: Careful rechecking with Table II. - One vehicle, Two persons → \(300 \times 2.5 = 750\) - One vehicle, 3+ persons → \(200 \times 5 = 1000\) - Two+ vehicles, Two persons → \(100 \times 3 = 300\) - Two+ vehicles, 3+ persons → \(50 \times 6 = 300\) Sum = \(2350\).

Final Answer: \[ \boxed{2350} \]

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