A girl standing on road holds her umbrella at 45° with the vertical to keep the rain away. If she starts running without umbrella with a speed of \(15\sqrt2\) \(kmh^{–1}\), the rain drops hit herhead vertically. The speed of rain drops with respect to the moving girl is
- \(30\) \(kmh^{–1}\)
- \(\frac{25}{\sqrt2}\) \(kmh^{-1}\)
- \(\frac{30}{\sqrt2}\) \(kmh^{-1}\)
- \(25\) \(kmh^{–1}\)
The Correct Option is C
Solution and Explanation
From graph,
\(V_{RG} =15\sqrt2tan\;45\degree\)
= \(15\sqrt2\)
= \(\frac{30}{\sqrt2}\)
Therefore, the correct option is (C): \(\frac{30}{\sqrt2}\) \(kmh^{-1}\)
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Concepts Used:
Speed and Velocity
The rate at which an object covers a certain distance is commonly known as speed.
The rate at which an object changes position in a certain direction is called velocity.
Difference Between Speed and Velocity:
Read More: Difference Between Speed and Velocity