Step 1: Since the temperature is constant, we apply Boyle's Law:
\[
P_1 V_1 = P_2 V_2
\]
Given:
\(P_1 = 1\) atm, \(V_1 = 500\) mL, \(P_2 = 2\) atm, \(V_2 = ?\)
Step 2: Substitute values into Boyle’s law:
\[
1 \times 500 = 2 \times V_2 \Rightarrow V_2 = \frac{500}{2} = 250 \text{ mL}
\]
Step 3: Therefore, the new volume at 2 atm is 250 mL.