Question:

A galvanometer with a scale divided into $100$ equal divisions has a current sensitivity of $10$ divisions per milliampere and a voltage sensitivity of $2$ divisions per millivolt. The galvanometer resistance will be

Updated On: Apr 26, 2024
  • $ 4 \, \Omega$
  • $ 5 \, \Omega$
  • $ 3 \, \Omega$
  • $7 \, \Omega$
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The Correct Option is B

Solution and Explanation

Given: current sensitivity = 10 div/mA and there are 100 division on the scale.
$\therefore$ Current required for full scale deflection.
$I_{g} = \frac{1}{10} \times100\,mA = 10 \,mA$
$ = 0.1 A $
Also voltage sensitivity = 2 div/mV
$\therefore$ voltage required for full scale deflection
$ V_{g} = \frac{1}{2} \times100mV $
$= 0.05V $
Galvanometer resistance is given by
$ G = \frac{V_{g}}{I_{g}} = \frac{0.05}{0.01} $
$= 5 \Omega $
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Concepts Used:

Electrical Instruments

There are various electrical instruments used to measure current, power, voltage, etc.  Some of them are briefly explained below:

Moving Coil Galvanometer

  • It is an electromagnetic device which measures small values of current.
  • Its working principle is that whenever a current loop is placed in a magnetic field, it experiences a certain torque. The value of that torque can be modified by modifying the current in the loop.
  • For a current carrying loop having N turns, and cross sectional area A, carrying current i, whenever it is placed in and along the direction of an external magnetic field B, it experiences a torque given by:

ԏ = NiAB

moving coil galvanometer