A galvanometer with a scale divided into $100$ equal divisions has a current sensitivity of $10$
divisions per milliampere and a voltage sensitivity of $2$ divisions per millivolt. The galvanometer resistance will be
Given: current sensitivity = 10 div/mA and there are 100 division on the scale. $\therefore$ Current required for full scale deflection. $I_{g} = \frac{1}{10} \times100\,mA = 10 \,mA$ $ = 0.1 A $ Also voltage sensitivity = 2 div/mV $\therefore$ voltage required for full scale deflection $ V_{g} = \frac{1}{2} \times100mV $ $= 0.05V $ Galvanometer resistance is given by $ G = \frac{V_{g}}{I_{g}} = \frac{0.05}{0.01} $ $= 5 \Omega $
There are various electrical instruments used to measure current, power, voltage, etc. Some of them are briefly explained below:
Moving Coil Galvanometer
It is an electromagnetic device which measures small values of current.
Its working principle is that whenever a current loop is placed in a magnetic field, it experiences a certain torque. The value of that torque can be modified by modifying the current in the loop.
For a current carrying loop having N turns, and cross sectional area A, carrying current i, whenever it is placed in and along the direction of an external magnetic field B, it experiences a torque given by: