Let the initial stock of all fruits be denoted by \( S \). Let the number of bananas be \( b \) and the number of apples be \( a \).
Stock of Mangoes \( = 40\% \) of \( S = \frac{2S}{5} \)
Total number of fruits sold = Mangoes Sold + Apples Sold + Bananas Sold
\( = \frac{2S}{10} + 96 + \frac{4a}{10} = \frac{S}{2} \) (Given)
\( \Rightarrow \frac{S}{5} + 96 + \frac{2a}{5} = \frac{S}{2} \)
Multiply both sides by 10 to eliminate denominators:
\( 2S + 960 + 4a = 5S \)
\( \Rightarrow 3S = 4a + 960 \)
\( \Rightarrow S = \frac{4a + 960}{3} = \frac{4a}{3} + 320 \)
For \( S \) to be an integer, \( a \) must be a multiple of 3. Also, from the term \( \frac{4a}{10} \), \( a \) must be a multiple of 5.
Hence, the smallest value of \( a \) that satisfies both conditions (LCM of 3 and 5) is \( a = 15 \)
Substitute into the formula for \( S \):
\( S = \frac{4 \times 15}{3} + 320 = 20 + 320 = 340 \)
Correct answer is (C): 340
An electricity utility company charges ₹7 per kWh. If a 40-watt desk light is left on for 10 hours each night for 180 days, what would be the cost of energy consumption? If the desk light is on for 2 more hours each night for the 180 days, what would be the percentage-increase in the cost of energy consumption?